In a , side BC is produced to D. If =50^ and =110^ then =? - Vidyadip

Question

In a $\triangle\text{ABC},$ side BC is produced to D. If $\angle\text{ABC}=50^\circ$ and $\angle\text{ACD}=110^\circ$ then $\angle\text{A}=?$

✓

Answer

60º
Solution:
$\angle\text{ACD}=\angle\text{B}+\angle\text{A}$ (Exterior angle property)
$\Rightarrow110^\circ=50^\circ+\angle\text{A}$
$\Rightarrow\angle\text{A}=60^\circ$

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