MCQ
In acidic medium, $\ce{K_2Cr_2O_7}$ shows oxidising action as represented in the half reaction $\ce{Cr_2O_7^{2-} + XH^{+} + Ye^{-} \rightarrow 2 A + ZH_2O,  X , Y , Z}$ and $A$ are respectively are:
  • A
    $8,6,4$ and $Cr _2 O _3$
  • B
    $14,7,6$ and $Cr ^{3+}$
  • C
    $8,4,6$ and $Cr _2 O _3$
  • D
    $14,6,7$ and $Cr ^{3+}$

Answer

The balanced reaction is,
$\ce{Cr_2O_7^{2-} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_2O}$
$X=14$
$Y=6$
$A=7$

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