MCQ
In acidic medium, equivalent weight of ${K_2}C{r_2}{O_7}$ $(mol.\,\,wt.\, = M)$ is
- A$M/3$
- B$M/4$
- ✓$M/6$
- D$M/2$
✓
Answer
Correct option: C.
$M/6$
(c) $C{r_2}O_7^{2 - } + 14{H^ + } + 6{e^-} \to 2C{r^{3 + }} + 7{H_2}O$
${\text{Equivalent}}\,\,{\text{weight}}\,\,{\text{of }}{K_2}C{r_2}{O_7}$
$ = \frac{{{\text{Molecular}}\,\,{\text{Mass}}}}{6}$$ = \frac{{294.2}}{6} = \frac{M}{6}$.
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