MCQ
In ammonium-phosphomolybdate, the oxidation state of Mo is ${ }^{+}$ $..........$.
- A$8$
- B$4$
- C$10$
- D$6$
Let $X =$ oxidation state of $Mo$ in $MoO _3$
$X +(-2) \times 3=0$
$X =+6$
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$A^+/A = \,-\,2.93\, Volt$, $B^+/B = 0.80\,V$
$C^{+2}/C = \,-\,2.37\, Volt$, $D^{+3}/D = \,-\,0.74\,V$
Increasing order of reducing power of these metals
