In an electrolyte $3.2 \times {10^{18}}$ bivalent positive ions drift to the right per second while $3.6 \times {10^{18}}$ monovalent negative ions drift to the left per second. Then the current is
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Net current ${i_{net}} = {i_{( + )}} + {i_{( - )}}$
$ = \frac{{{n_{( + )}}{q_{( + )}}}}{t} + \frac{{{n_{( - )}}{q_{( - )}}}}{t}$
$ = \frac{{{n_{( + )}}}}{t} \times 2e + \frac{{{n_{( - )}}}}{t} \times e$
$= 3.2 \times {10^{18}} \times 2 \times 1.6 \times 10^{-19} + 3.6 \times {10^{18}} \times 1.6 \times 10^{-19}$
$= 1.6\, A$ (towards right)
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