In an LPP, the objective function is always - Vidyadip

MCQ

In an LPP, the objective function is always

A
Non-linear
✓
Linear
C
Quadratic
D
Cubic

✓

Answer

Correct option: B.

Linear

(b)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

A vector whose initial and terminal points coincide, is:

If $f(x) = {\mathop{\rm sgn}} ({x^3})$, then

Find the equation of a line passing through a point $(2,-1,3)$ and parallel to the line $\vec{r}=(\hat{i}+\hat{j})+\lambda(2 \hat{i}+\hat{j}-2 \hat{k})$.

If $x, y, z$ are not all simultaneously equal to zero, satisfying the system of equations

($\sin 3 \theta ) x - y + z = 0$
($\cos 2 \theta ) x + 4 y + 3 z = 0$
$2 x + 7 y + 7 z = 0$
then the number of principal values of $\theta$ is

Let $y = y(x)$ be the solution of the differential equation $\frac{{dy}}{{dx}} + y\,\tan \,x = 2x\, + \,{x^2}\,\tan \,x\,,\,x\, \in \,\left( { - \frac{\pi }{2},\frac{\pi }{2}} \right),$ such that $y(0) = 1.$ Then

Let $e^{f(x)} = ln x .$ If $g(x)$ is the inverse function of $f(x)$ then $g ‘ (x)$ equals to :

The solution of $\frac{{dy}}{{dx}} + y = {e^{ - x}},\,\,y(0) = 0$, is

The unit vector perpendicular to both $i + j$ and $j + k$ is

The points $(k − 1, k + 2), (k, k + 1), (k + 1, k)$ are collinear for:

What is the general solution of the differential equation $e ^{ y ^{\prime}}= x ?$