MCQ
In any $\triangle\text{ABC},2(\text{bc}\cos\text{A + ca}\cos\text{B + ab}\cos\text{C})=$
- A$\text{abc}$
- B$\text{a + b + c}$
- ✓$\text{a}^2+\text{b}^2+\text{c}^2$
- D$\frac{1}{\text{a}^2}+\frac{1}{\text{b}^2}+\frac{1}{\text{c}^2}$
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= 17 is