MCQ
In $CO_2, C$ is $sp$ hybridised using $s$ and $p_x$ orbitals then
- A$CO_2$ is present in $YZ$ plane
- B$CO_2$ is not present in $XY$ plane
- C$P_z$ orbital of $O$ is used for $\sigma $ bonding
- ✓$CO_2$ is present in infinite planes
✓
Answer
Correct option: D.
$CO_2$ is present in infinite planes
d
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