- A$0$
- ✓$2.83$
- C$3.87$
- D$4.92$

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$N{H_4}HS(s) \rightleftharpoons N{H_3}(g) + H_2S(g)$
Predict the effect of adding the inert gas
$I.$ $CH_3 -CH = CH_2$ $\xrightarrow[{{\text{(CC}}{{\text{l}}_4}{\text{ )}}}]{{{\text{C}}{{\text{l}}_2}}}$ $\begin{array}{*{20}{c}}
{Cl\,\,}\\
{\,\,|\,\,\,\,\,}\\
{C{H_3} - CH - C{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl}
\end{array}$
$II.$ $\begin{array}{*{20}{c}}
O\\
{||}\\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow[{{}^\Theta OH}]{{{\text{HCN}}}}$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,OH}\\
|\\
{C{H_3} - C - C{H_3}}\\
|\\
{\,\,\,\,\,CN}
\end{array}$
$III.$ $CH_3-CH_2-CH_3$ $\xrightarrow[{hv}]{{C{l_2}}}$ $\begin{array}{*{20}{c}}
{Cl\,\,}\\
{|\,\,\,\,}\\
{C{H_3} - CH - C{H_3}}
\end{array}$