MCQ
In $\Delta$PQR, m$\angle$PQR = 90°, seg QS $\perp$ hyp PR then.
- ✓$QS ^2= PS \times RS$
- B$PS ^2= OS \times PR$
- C$PR ^2= QS \times PS$
- D$PR ^2= QS ^2 \times PS ^2$
✓
Answer
Correct option: A.
$QS ^2= PS \times RS$
A
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