MCQ
In electrolysis of dilute ${H_2}S{O_4}$using platinum electrodes
- ✓${H_2}$ is evolved at cathode
- B$N{H_3}$ is produced at anode
- C$C{l_2}$ is obtained at cathode
- D${O_2}$ is produced
✓
Answer
Correct option: A.
${H_2}$ is evolved at cathode
a
(a)When platinum electrodes are dipped in dilute solution ${H_2}S{O_4}$ than ${H_2}$ is evolved at cathode.
(a)When platinum electrodes are dipped in dilute solution ${H_2}S{O_4}$ than ${H_2}$ is evolved at cathode.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The freezing point of equimolal aqueous solution will be highest for
Of the following, non-existent compound is
IUPAC name of the compound is:
Relation between amino acids and proteins is similar to the one present between:
Number of metamers represented by molecular formula ${C_4}{H_{10}}O$ is
→The set of correct statements is:
→$(i)$ Manganese exhibits $+7$ oxidation state in its oxide.
$(ii)$ Ruthenium and Osmium exhibit $+8$ oxidation in their oxides.
$(iii)$ $Sc$ shows $+4$ oxidation state which is oxidizing in nature.
$(iv)$ $Cr$ shows oxidising nature in $+6$ oxidation state.
One mole of potassium dichromate completely oxidises the following number of moles of ferrous sulphate in acidic medium
The following compound is used as
Geometry of reaction intermediate in $S{N^1}$ reaction is
→The calculated spin only magnetic moments $(BM)$ of the anionic and cationic species of ${\left[ {Fe{{\left( {{H_2}O} \right)}_6}} \right]_2}$ and $\left[ {Fe{{\left( {CN} \right)}_6}} \right]$ , respectively, are:
→