MCQ
In Fig. $ABCD$ is a cyclic quadrilateral. If $\angle\text{BAC}=50^\circ$ and $\angle\text{DBC}=60^\circ$ then find $\angle\text{BCD}=\ ?$
- A$50^\circ$
- B$55^\circ$
- C$60^\circ$
- ✓$70^\circ$
✓
Answer
Correct option: D.
$70^\circ$
Here, $\angle\text{BAC}=50^\circ$ (angles in same segment are equal)
In $\triangle\text{BCD},$ we have
$\angle\text{BCD}=180^\circ−(\angle\text{BDC}+\angle\text{DBC})$
$=180^\circ−(50^\circ+60^\circ)$
$= 70^\circ$
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