MCQ
- A90º
- B85º
- C95º
- D100º
✓
Answer
- 95º
Solution:
Given,
AOB = Straight line
$\angle\text{AOC}+\angle\text{BOD}=85^\circ$
$\angle\text{AOC}+\angle\text{COD}+\angle\text{BOD}=180^\circ $(Linear pair)
$85^\circ+\angle\text{COD}=180^\circ$
$\angle\text{COD}=95^\circ.$
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