100º Solution: Given that, AB || CD Produce P to Q so that PQ || AB || CD $\angle\text{BAP}+\angle\text{APQ}=180^\circ$ (Interior angle) $132^\circ+\angle\text{APQ}=180^\circ$ $\angle\text{APQ}=48^\circ\text{(i)}$ $\angle\text{APC}=\angle\text{APQ}+\angle\text{QPC}$ $148^\circ=48^\circ+\angle\text{QPC}$ [From (i)] $\angle\text{QPC}=100^\circ$ $\angle\text{QPC}+\angle\text{PCD}=180^\circ$ (Interior angles) $100^\circ+\angle\text{PCD}=180^\circ$ $\angle\text{PCD}=80^\circ$ $\angle\text{PCD}+\text{x}=180^\circ$(Linear pair) $80^\circ+\text{x}=180^\circ$ $\text{x}=100^\circ.$
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