MCQ
- A$45^{\circ}$
- B$65^{\circ}$
- ✓$55^{\circ}$
- D$621 / 2^{\circ}$
✓
Answer
Correct option: C.
$55^{\circ}$
(c)$55^{\circ}$
We find that the circle touches the sides of quadrilateral $A B C D$. Therefore,
$\angle A O B+\angle C O D=180^{\circ} \qquad$ [See result at S.No. 22 at page 8.2 ]
$\Rightarrow \quad 125^{\circ}+\angle C O D=180^{\circ} \Rightarrow \angle C O D=55^{\circ}$
We find that the circle touches the sides of quadrilateral $A B C D$. Therefore,
$\angle A O B+\angle C O D=180^{\circ} \qquad$ [See result at S.No. 22 at page 8.2 ]
$\Rightarrow \quad 125^{\circ}+\angle C O D=180^{\circ} \Rightarrow \angle C O D=55^{\circ}$
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