MCQ
- A70º
- B40º
- C100º
- D30º
✓
Answer
- 40º
Solution:
Given that,
l ll m
Let, l || m and transversal cuts them and
$\angle1=70^\circ$
$\angle3=20^\circ$
$\angle4=30^\circ$
$\angle1+\angle2=180^\circ$ (Interior angle)
$\angle2=110^\circ\text{(i})$
$\angle2=\angle5$ (Vertically opposite angle)
$\angle5=110^\circ\text{(ii)}$
$\angle5+\angle3+\angle4=180^\circ$(Sum of angles of a triangle is 180o)
110º + x + 30º = 180º
x = 40º.
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