MCQ
- A85º
- B65º
- C20º
- D45º
✓
Answer
- 45º
Solution:
l || m
Let transversal be n and $\angle1=65^\circ$
$\angle2=20^\circ$
$\angle3=\text{x}$
Since,
l || m and n cuts them so,
$\angle1+\angle4=180^\circ$ (Co. interior angle)
$65^\circ+\angle4=80^\circ$
$\angle4=115^\circ\text{(i)}$
$\angle4=\angle5=115^\circ$ (Vertically opposite angle)
$\angle2+\angle5+\angle3=180^\circ$
20º + 115º + x = 180º
x = 45º.
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