Answer

  1. You may observe that in $\triangle$ AOD and $\triangle$ BOC,
    OA = OB (Given)
    OD = OC
    Also, since $\angle$ AOD and $\angle$ BOC form a pair of vertically opposite angles,
    we have $\angle$ AOD = $\angle$ BOC
    So, $\triangle$ AOD $\cong$ $\triangle$ BOC (by the SAS congruence rule)
  2. In congruent triangles AOD and BOC, the other corresponding parts are also equal.
    So, $\angle$ OAD = $\angle$ OBC and these form a pair of alternate angles for line segments AD and BC.
    Therefore, AD || BC

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