You may observe that in $\triangle$ AOD and $\triangle$ BOC, OA = OB (Given) OD = OC Also, since $\angle$ AOD and $\angle$ BOC form a pair of vertically opposite angles, we have $\angle$ AOD = $\angle$ BOC So, $\triangle$ AOD $\cong$ $\triangle$ BOC (by the SAS congruence rule)
In congruent triangles AOD and BOC, the other corresponding parts are also equal. So, $\angle$ OAD = $\angle$ OBC and these form a pair of alternate angles for line segments AD and BC. Therefore, AD || BC
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