In figure 1.73, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then A ( ABC ) A… - Vidyadip

Question

In figure 1.73, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then $\frac{ A (\triangle ABC )}{ A (\triangle DCB )}=?$

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Answer

We know that, Area of triangle $=\frac{1}{2} \times$ base $\times$ height
$\begin{aligned}
& \frac{A(\triangle A B C)}{A(\triangle D C B)}=\frac{\frac{1}{2} \times B C \times A B}{\frac{1}{2} \times B C \times D C} \\
= & \frac{A B}{D C} \\
= & \frac{6}{8} \\
= & \frac{3}{4}
\end{aligned}$

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