Question
In figure, AOB is a straight line. If $\angle\text{AOC}+\angle\text{BOD}=85^\circ,$ then $\angle\text{COD}=$
- 85°
- 90°
- 95°
- 100°
✓
Answer
- 95°
From figure, we can see
$\angle\text{AOC}+\angle\text{COD}+\angle\text{BOD}=180^\circ$
But,
$\angle\text{AOC}+\angle\text{BOD}=85^\circ$ [Given]
$\Rightarrow\ 85^\circ+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=95^\circ$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
→→→→→→→
Write the correct answer in the following:
Zero of the zero polynomial is.
Zero of the zero polynomial is.
In the 'less than' type of ogive the cumulative frequency is plotted against:
Given the class intervals 1-10, 11-20, 21-30, …, then 20 is considered in class:
The mean of 100 items was found to be 64. Later on it was discovered that two items were misread as 26 and 9 instead of 36 and 90 respectively. The correct mean is:
-
64.86
-
65.31
-
64.91
-
64.61
In the class intervals 10-20, 20-30 the number 20 is included in:
If $x^2 + kx - 3 = ( x - 3) ( x + 1),$ then the value of$\ 'k\ '$ is:
→The number $1.\overline{27}$ in the form $\frac{\text{p}}{\text{q}},$ where p and q are integers and $\text{q}\neq0,$ is:
→- $\frac{14}{9}$
- $\frac{14}{11}$
- $\frac{14}{13}$
- $\frac{14}{15}$
Which of the following polynomials has $(-3)$ as a zero?
→