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Circles — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsCircles1 Mark
MCQ
In figure, if $\angle\text{AOB}=125^\circ,$ then $\angle\text{COD}$ is equal to :
  • A
    $62.5^\circ$
  • B
    $45^\circ$
  • C
    $35^\circ$
  • ✓
    $55^\circ$
✓

Answer

Correct option: D.
$55^\circ$
we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.
i.e., $\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=180^\circ-\angle\text{AOB}$
$=180^\circ - 125^\circ = 55^\circ$

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