In given arrangement $E_1 = 5\, volts$ $E_2 = 7\, volt$ balancing length is $6\,m$ if terminals of $E_2$ are reversed then new balancing length will be
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On reversing the cell $\mathrm{E}_{2}$ cbt become
$\mathrm{E}^{1}=\mathrm{E}_{2}-\mathrm{E}_{1}=2 \mathrm{\,V}$
we can't get balancing point.
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