- A$C_6H_5CHO$
- ✓$Ph - OH$
- C$\begin{array}{*{20}{c}}
{{C_6}{H_5} - C{H_2} - C - C{H_2}OH} \\
{\,\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,O}
\end{array}$ - D$CH_3CHO$
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Under standard conditions, the number of moles of $M ^{+}$oxidized when one mole of $X$ is converted to $Y$ is $\left[ F =96500 \ C \ mol ^{-1}\right]$
$\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq}),(1 \mathrm{M}) \| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq})\right| \mathrm{Pt}(\mathrm{s})$
The fraction of total iron present as $\mathrm{Fe}^{3+}$ ion at the cell potential of $1.500\, \mathrm{~V}$ is $\mathrm{X} \times 10^{-2}$. The value of $x$ is $.....$ (Nearest integer).
$\left(\right.$ Given $\left.E_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^{0}=0.77\, \mathrm{~V}, \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{0}=-0.76 \,\mathrm{~V}\right)$
