In given figure, the potentiometer wire $AB$ has a resistance of $5$ $\Omega$ and length $10\, m$. The balancing length $AM$ for the $emf$ of $0.4\, V$ is ............... $m$
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(d) $E = \frac{e}{{(R + {R_h} + r)}}.\frac{R}{L} \times l$$ \Rightarrow $ $0.4 = \frac{5}{{(5 + 45 + 0)}} \times \frac{5}{{10}} \times l$
$ \Rightarrow $ $l = 8\, m$
$ \Rightarrow $ $l = 8\, m$
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