In Kjeldahl's method for the estimation of nitrogen, the formula …

[Given : $\mathrm{K}_{\mathrm{f}}=1.86 \,\mathrm{~K} \,\mathrm{~kg} \,\mathrm{~mol}^{-1} ;$ Density of water $=$ $1.00 \,\mathrm{~g}\, \mathrm{~cm}^{-3} ;$ Freezing point of water $\left.=273.15\, \mathrm{~K}\right]$

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When the aqueous solution of $0.5\, mole $ $HN{O_3}$ is mixed with the $0.3\, mole$ of $O{H^ - }$ solution, then what will be the liberated heat.......$kJ$ (Enthalpy of neutralization is $= 57.1 \,kJ$ )

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The heat of neutralization of $HCl$ by $NaOH$ under certain condition is $-55.9\,\, kJ$ and that of $HCN$ by $NaOH$ is $-12.1\,\, kJ$. the heat of ionization of $HCN$ is .............. $\mathrm{kJ \,mol}^{-1}$

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Consider the following reaction

$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C - O - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,\,$ $\xrightarrow[{(1\,Mole)}]{{HI}}$ Products

The main products of reaction will be

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Which of following will gives phenol with $O_2$ in presence of acid catalyst ?

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Which of the following equation is incorrect written?

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Given :

$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$

$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$

Based on the data given above, strongest oxidising agent will be :

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The correct arrangement for decreasing order of electrophilic substitution for above compounds