MCQ
In $\left[ {Cu\,{{\left( {N{H_3}} \right)}_4}} \right]\,S{O_4},\,\,;\,Cu$ has following hybridization
- ✓$ds{p^2}$
- B$s{p^3}$
- C$s{p^2}$
- D$s{p^3}{d^2}$
The $Cu$ atom is in form of $Cu ^{+2}$ in the compound.
In $Cu ^{+2}$, the electronic configuration would be $1 s^2 \,2 s^2 \,2 p^6\, 3 s^2\, 3 p^6 \,3 d^9 \,4 s^0$
So, there would be a rearrangement of electrons in $Cu ^{2+}$ because of the $NH _3$ ligand (which is a strong one). And the last electron in the $d$-orbital would be out waiting for the $N'$s electrons to fill up first.
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$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$
$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$ The $\Delta H ^\theta$ for the reaction $......$.$C ($ graphite $)+\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ is
$(I)\,\,HCHO$ $ (II)\,\,CH_3CHO$
$(III)$ Acetone $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{(IV)\,\,\,Et - C - Et}
\end{array}$
$\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq}),(1 \mathrm{M}) \| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq})\right| \mathrm{Pt}(\mathrm{s})$
The fraction of total iron present as $\mathrm{Fe}^{3+}$ ion at the cell potential of $1.500\, \mathrm{~V}$ is $\mathrm{X} \times 10^{-2}$. The value of $x$ is $.....$ (Nearest integer).
$\left(\right.$ Given $\left.E_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^{0}=0.77\, \mathrm{~V}, \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{0}=-0.76 \,\mathrm{~V}\right)$