MCQ
In Melde's experiment, the string vibrates in $4$ loops when a $50$ gram weight is placed in the pan of weight $15$ gram. To make the string to vibrates in 6 loops the weight that has to be removed from the pan is
  • A
    $0.0007 \mathrm{~kg} w$
  • B
    $0.0021 \mathrm{~kg} w$
  • $0.036 \mathrm{~kg} \mathrm{wt}$
  • D
    $0.0029 \mathrm{~kg} w t$

Answer

Correct option: C.
$0.036 \mathrm{~kg} \mathrm{wt}$
Frequency of vibration of string is given by
$ln=\frac{p}{2}l\sqrt{\frac{T}{m}} \Rightarrow p \sqrt{T}=\text { constant } \Rightarrow \frac{p_1}{p_2}=\sqrt{\frac{T_2}{T_1}} $
$\text { Hence } \frac{4}{6}=\sqrt{\frac{T_2}{(50+15)}} g m-\text { force}\Rightarrow T_2=28.8 \mathrm{gm}-f$
Hence weight removed from the pan$=T_1T_2=65-28.8=3.62\ \mathrm{gm} \ \text {-force }=0.036 \mathrm{~kg} \text {-f. }$

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