MCQ
In MgCl2, the oxidation number of chlorine is:
- A+1
- B+2
- C−1
- D0
Explanation:
In MgCl2, oxidation number of Cl is:
⇒ 2 + 2x = 0
⇒ x = −1.
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$(I)$ electron affinity of $Y$ is high $(II)$ ionization energy of $X$ is low
$(III)$ lattice energy of $XY$ is high $(IV)$ lattice energy of $XY$ is low
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