MCQ
In $N{H_4}N{O_2},$ the oxidation number of nitrogen will be
- A$3$
- B$5$
- ✓$-3$ and $+ 3$
- D$+ 3 $ and $+ 5$
✓
Answer
Correct option: C.
$-3$ and $+ 3$
c
(c) $\mathop {N{H_4}N{O_2}}\limits_{({\rm{Oxidation}}\,{\rm{number}})} $ $\rightleftharpoons$ $\mathop {\mathop {\mathop N\limits^* H_4^ + }\limits_{x + 4 = + 1} }\limits_{x = 1 - 4 = - 3} + \mathop {\mathop {\mathop N\limits^* O_2^ - }\limits_{x - 4 = - 1} }\limits_{x = + 3} $
(c) $\mathop {N{H_4}N{O_2}}\limits_{({\rm{Oxidation}}\,{\rm{number}})} $ $\rightleftharpoons$ $\mathop {\mathop {\mathop N\limits^* H_4^ + }\limits_{x + 4 = + 1} }\limits_{x = 1 - 4 = - 3} + \mathop {\mathop {\mathop N\limits^* O_2^ - }\limits_{x - 4 = - 1} }\limits_{x = + 3} $
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