MCQ
In $\mathrm{Ni}(\mathrm{CO})_4,$ the oxidation state of $\ce{Ni}$ is?
- ✓$4$
- BZero
- C$2$
- D$8$
✓
Answer
Correct option: A.
$4$
In nickel tetracarbonyl, the oxidation state for nickel is assigned as zero. The formula conforms to the $18-$ electron rule. The molecule is tetrahedral, with four carbonyl $($carbon monoxide$)$ ligands attached to nickel.
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