MCQ
In $P_4\ ($tetrahedral$):$
- AEach $P$ is joined to four $P.$
- ✓Each $P$ is joined to three $P.$
- CEach $P$ is joined to two $P.$
- D$P_4$ does not exist.
✓
Answer
Correct option: B.
Each $P$ is joined to three $P.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The molarity of a solution of $N{a_2}C{O_3}$ having $10.6\,g/500\,ml$ of solution is ......... $M$
→In Williamson synthesis of mixed ether having a primary and a tertiary alkyl group if tertiary halide is used, then
The reaction of $NO$ with $N _{2} O _{4}$ at $250\, K$ gives :
→Which of the following compound show optical isomerism?
What is the correct IUPAC name of the given compound?
A solution is prepared by dissolving $0.6\, g$ of urea (molar mass $= 60\, g\, mol^{-1}$) and $1.8\, g$ of glucose (molar mass $= 180\, g\, mol^{-1}$) in $100\, mL$ of water at $27\,^oC$. The osmotic pressure of the solution is : ............. $\mathrm{atm}$ $(R = 0.08206\, L\, atm\, K^{-1}\, mol^{-1})$
→What current strength in amp. will be required to liberate $10\, g$ of chlorine from $NaCl$ solution in one hour ............. $\mathrm{amp}$
→If $CO$ ligands are substituted by $NO$ in respective neutral carbonyl compounds then which of the following will not be correct formula ?
→Given below are two statements. One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
→Assertion $A$: Amylose is insoluble in water.
Reason $R$: Amylose is a long linear molecule with more than $200$ glucose units.
In the light of the above statements, choose the correct answer from the options given below.
Major; product $(A)$ is
→