In potentiometer a balance point is obtained, when
AThe $e.m.f.$ of the battery becomes equal to the $e.m.f.$ of the experimental cell
BThe $p.d.$ of the wire between the $+ve$ end to jockey becomes equal to the $e.m.f.$ of the experimental cell
CThe $p.d.$ of the wire between $+ve$ point and jockey becomes equal to the $e.m.f.$ of the battery
DThe $p.d.$ across the potentiometer wire becomes equal to the $e.m.f.$ of the battery
Easy
Download our app for free and get started
BThe $p.d.$ of the wire between the $+ve$ end to jockey becomes equal to the $e.m.f.$ of the experimental cell
b (b) In general, if the arrangement is not balanced, there will be a potential difference across the galvanometer, $G.$ This will only be zero means balance when the $p.d.$ of the wire between the $+ve$ end of battery to jockey becomes equal to the $e.m.f.$ of the experimental cell.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$A$ potentiometer wire has length $10\, m$ and resistance $10\,\Omega$ . It is connected to a battery of $EMF$ $11\, volt$ and internal resistance $1\, \Omega$ , then the potential gradient in the wire is ............... $V/m$
To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances $R_1 = 9970\,\Omega,$ $R_2 = 30\,\Omega$ and $R_3 = 0\,\Omega.$ The deflection in the galvanometer is $d$. With $R_3 = 107\,\Omega$ the deflection changed to $\frac {d}{2}$The galvanometer resistance is approximately ............... $\Omega$
A current of $2\,A$ flows through a $2\,\Omega$ resistor when connected across a battery. The same battery supplies a current of $0.5\,\, A$ when connected across a $9 \,\,\Omega$ resistor. The internal resistance of the battery is
An unknown resistance $R_1$ is connected in series with a resistance of $10 \,\Omega$. This combinations is connected to one gap of a meter bridge while a resistance $R_2$ is connected in the other gap. The balance point is at $50\, cm$. Now, when the $10 \,\Omega$ resistance is removed the balance point shifts to $40\, cm$. The value of $R_1$ is (in $ohm$)
Carbon resistor has resistance specified by three bands having colour red, yellow and black. If this resistor is cut into two pieces of equal length then the new colour code of each one will be (Neglect tolerance of $4^{th}$ band)
$62.5 \times {10^{18}}$ electrons per second are flowing through a wire of area of cross-section $0.1\,{m^2}$, the value of current flowing will be ............ $A$
A certain piece of silver of given mass is to be made like a wire. Which of the following combination of length $(L)$ and the area of cross-sectional $(A) $ will lead to the smallest resistance