$80^{\circ}$
In $\square P Q R S$,
$\angle R S P=80^{\circ}$ $\quad$ $\ldots$ [ Given ]
$\angle R Q T=\angle R S P \quad \ldots$ [ The exterior angle of a cyclic quadrilateral is equal to the interior opposite angle ]
$\therefore \angle R Q T=80^{\circ} \text {. }$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.