MCQ
In Pyridine number of conjugated electrons are :


- ✓$6$
- B$8$
- C$1$
- D$5$


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$(I)\, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is polar molecule
$(II)\, CH_3 \widehat{P} CH_3$ bond angles are equal in $(CH_3)_3P(CF_3)_2$ molecule
$(III)\,PF_3$ will be more soluble in polar solvent than $SiF_4$