In $SHM,$ acceleration versus displacement (from mean position) graph :
Ais always a straight line passing through origin and slope ${-1}$
Bis always a straight line passing through origin and slope $+1$
C
is a straight line not necessarily passing through origin
D
none of the above
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D
none of the above
d $a=-\omega^{2}\left(x-x_{o}\right)$
so graph of $a$ vs $x$ is a straight line having slope $-\omega^{2}$
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