Question
In square $\text{ABCD}; A = (3, 4), B = (-2, 4)$ and $C = (-2, -1)$. By plotting these points on a graph paper, find the co$-$ordinates of vertex $D$. Also, find the area of the square.
✓
Answer
Given that in square $\text{ABCD} ; A(3,4), B(-2,4)$ and $C(-2,-1)$
After plotting the given points $A(3,4), B(-2,4)$ and $C(-2,-1)$ on a graph paper;
joining $B$ with $C$ and $B$ with $A$.
From the graph it is clear that the vertical distance between the points $B (-2,4)$ and $C (-2,-1)$ is $5$ units and the horizontal distance between the points $B (-2,4)$ and $A (3,4)$ is $5$ units,
$\therefore$ the vertical distance between the points $A (3,4)$ and $D$ must be 5 units and the horizontal distance between the points $C(-2,-1)$ and $D$ must be $5$ units. Now complete the square $\text{ABCD}$
As is clear from the graph $D(3,-1)$
Now the area of the square $\text{ABCD}$ is given by area of $\text{ABCD}=(\text { side })^2=(5)^2=25$ units
After plotting the given points $A(3,4), B(-2,4)$ and $C(-2,-1)$ on a graph paper;
joining $B$ with $C$ and $B$ with $A$.
From the graph it is clear that the vertical distance between the points $B (-2,4)$ and $C (-2,-1)$ is $5$ units and the horizontal distance between the points $B (-2,4)$ and $A (3,4)$ is $5$ units,
$\therefore$ the vertical distance between the points $A (3,4)$ and $D$ must be 5 units and the horizontal distance between the points $C(-2,-1)$ and $D$ must be $5$ units. Now complete the square $\text{ABCD}$
As is clear from the graph $D(3,-1)$
Now the area of the square $\text{ABCD}$ is given by area of $\text{ABCD}=(\text { side })^2=(5)^2=25$ units
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