MCQ
In the above reaction '$X$' stands for


- ✓$N{H_2}$
- B$SnC{l_2}$
- C$Cl$
- D$NH_4^ + C{l^ - }$


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$\mathop {Pt\,|\,C{l_2}\left( g \right)}\limits_{\left( {0.4\,bar} \right)} \,|\,\mathop {C{l^ - }\left( {aq.} \right)}\limits_{0.1\,M} \,||\,\,\mathop {C{l^ - }\left( {aq.} \right)}\limits_{0.01} \,|\,\mathop {C{l_2}\left( g \right)\,|\,Pt}\limits_{0.2\,bar} $
the measured potential at $298\, K$ is .............. $\mathrm{V}$
$Cu(s) + 2Ag{^+}_{(aq)} \to Cu^{+2}_{(aq)} + 2Ag(s)$
is $10 \times 10^{15}$, calculate the $E_{cell}^o$ of the reaction of $298\,K$
[${2.303\,\frac{{RT}}{F}}$ at $298\,K$ $=0.059\,V$]