Question
In the adjoining figure, ABCD is a parallelogram. Line segments $A X$ and $C Y$ bisect $\angle A$ and $\angle C$ respectively.
Prove that:
(i) $\triangle ADX \cong \triangle CBY$
(ii) $AX = CY$
(iii) $A X \| C Y$
(iv) AYCX is a parallelogram.

Prove that:
(i) $\triangle ADX \cong \triangle CBY$
(ii) $AX = CY$
(iii) $A X \| C Y$
(iv) AYCX is a parallelogram.

