Question
In the adjoining figure, ABCD is a parallelogram. P is a point on DC such that ar $(\triangle APD )=25 cm^2$ and ar $(\triangle BPC )$ $=15 cm^2$. Calculate :(i) ar ( $\| gm ABCD$ )
(ii) $DP : PC$.
(ii) $DP : PC$.
✓
Answer
(i) $80 cm^2$
(ii) $5: 3$
(ii) $5: 3$
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