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Triangles — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsTriangles1 Mark
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Answer

  1. 50º
    Solution:
    In triangle ABC, $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ$ (Given)
    $\angle\text{BAC} + \angle\text{ABC} + \angle\text{BCA} = 180^\circ$
    $\angle\text{BAC} = 50^\circ$
    Also $\angle\text{ACD} = 50^\circ$ (Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$)

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