MCQ
In the complex $Fe(CO)_x,$ the value of $x$ is :
- A$3$
- ✓$4$
- C$5$
- D$6$
✓
Answer
Correct option: B.
$4$
b
$B a\left|B r F_4\right| \rightarrow B a^{+2}+B r F_4^{-1}$
$B a\left|B r F_4\right| \rightarrow B a^{+2}+B r F_4^{-1}$
As each fluoride contains $-1$ charge, so $Br$ is in $+3$ oxidation state.
So, the name of complex is barium tetrafluorobromate(III).
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