MCQ
In the circuit shown, a potential difference of $60\,V$ is applied across $AB$. The potential difference between the point $M$ and $N$ is.....$V$
- A$10$
- B$15$
- C$20$
- ✓$30$
$V_{1}: V_{2}: V_{3}=\frac{1}{2 C}: \frac{1}{C}: \frac{1}{2 C}$
$V_{1}: V_{2}: V_{3}=\frac{1}{2}: \frac{1}{2}: \frac{1}{2}$
$V_{1}: V_{2}: V_{3} \equiv 1: 2: 1$
$V_{2}=\frac{2}{4} \times 60 V=30 V$
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