Question
 In the circuit shown below, calculate the current flowing through $20V$ cell.
Image

Answer

Here, we can apply Kirchhoff’s loop rule in closed loops $\text{ADCBA, AEFBA, AHGBA,}$ and $\text{AIJBA.}$ Thus, we get
$20 + 10 – 5I_1 = 0 \rightarrow I_1 = 6A$
$-5 + 20 – 15I_2 = 0 \rightarrow I_2 = 1A$
$25 + 20 – 10I_3 = 0 \rightarrow I_3 = 4.5A$
$-15 + 20 – 5I_4 = 0 \rightarrow I_4 = 1A$
Therefore, the current flowing through the $20V$ cell $= 6 + 1 + 4.5 + 1 = 12.5A$

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