In the circuit shown below, The reading of the voltmeter $V$ is ...........
A$12$
B$8$
C$20$
D$16$
Medium
Download our app for free and get started
A$12$
a (a) In the following circuit potential difference between
$C$ and $A$ is ${V_C} - {V_A} = 1 \times 4 = 4$ ……$(i)$
$C$ and $B$ is ${V_C} - {V_B} = 1 \times 16 = 16$ ……$(ii)$
On solving equations $(i)$ and $(ii)$ we get
${V_A} - {V_B} = 12\,V$.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$A$ Wheatstone's bridge is balanced with a resistance of $625\, \Omega$ in the third arm, where $P, Q$ and $S$ are in the $1^{st}, 2^{nd}$ and $4^{th}$ arm respectively. If $P$ and $Q$ are interchanged, the resistance in the third arm has to be increased by $51\,\Omega$ to secure balance. The unknown resistance in the fourth arm is ............. $\Omega$
Two resistors $400\, \Omega$ and $800\, \Omega$ are connected in series across a $6 V$ battery. The potential difference measured by a voltmeter of $10\, k \Omega$ across $400\, \Omega$ resistor is close to$....V$
Two wires that are made up of two different materials whose specific resistance are in the ratio $2 : 3$, length $3 : 4$ and area $4 : 5$. The ratio of their resistances is
In a potentiometer circuit there is a cell of $e.m.f.$ $2\, volt$, a resistance of $5\, ohm$ and a wire of uniform thickness of length $1000\, cm$ and resistance $15\, ohm$. The potential gradient in the wire is
Figure $(i)$ below shows a Wheatstone's bridge in which $P, Q, R$ and $S$ are fixed resistances, $G$ is a galvanometer and $B$ is a battery. For this particular case, the galvanometer shows zero deflection. Now, only the positions of $B$ and $G$ are interchanged, as shown in figure $(ii)$. The new deflection of the galvanometer
A $220 \; V , 50 \; Hz$ AC source is connected to a $25 \; V$, $5 \; W$ lamp and an additional resistance $R$ in series (as shown in figure) to run the lamp at its peak brightness, then the value of $R$ (in ohm) will be
Two identical cells each of emf $1.5 \,V$ are connected in parallel across a parallel combination voltmeter connected in the circuit measures $1.2 \,V$.
The internal resistance of each cell is.................$\Omega$