Question
In the circuit shown in figure the maximum output voltage $V_0$ is....$ V$
✓
Answer
(b)For the positive half cycle of input the resulting network is shown below
==>$(V_0)max =$$\frac{1}{2}{({V_i})_{\max }} = \frac{1}{2} \times 10 = 5\,V.$
==>$(V_0)max =$$\frac{1}{2}{({V_i})_{\max }} = \frac{1}{2} \times 10 = 5\,V.$
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