In the circuit shown in figure, the resistance of voltmeter is $6\, k\Omega $. The voltmeter reading will be ................. $\mathrm{V}$
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$\mathrm{R}=\frac{3 \times 6}{3+6}=2 \mathrm{\,K} \Omega$

voltage reading:

$\mathrm{V}=\frac{2}{2+2} \times 10=5 \mathrm{\,Volt}$

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