In the circuit shown, the point ‘$B$’ is earthed. The potential at the point ‘$A$’ is ............. $V$
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Current in the given circuit $i = \frac{{50}}{{(5 + 7 + 10 + 3)}} = 2\,A$
Potential difference between $A$ and $B$ ${V_A} - {V_B} = 2 \times 12$
$ \Rightarrow $ ${V_A} - 0 = 24\,V$ $ \Rightarrow $ ${V_A} = 24\,V$
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