In the circuit, the potential difference across $PQ$ will be nearest to .............. $V$
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Potential difference across $PQ$ i.e. p.d. across the resistance of $20$
$\Omega$, which is $V = i × 20$ and $i = \frac{{48}}{{(100 + 100 + 80 + 20)}} = 0.16\,A$
$V = 0.16 \times 20 = 3.2\,V$.
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