MCQ
In the electric network shown, when no current flows through the $4\, \Omega $ resistor in the arm $EB$, the potential difference between the points $A$ and $D$ will be ............... $V$


- A$6$
- B$3$
- ✓$5$
- D$4$

$\mathrm{V}_{\mathrm{D}}=0\, \mathrm{V}$
$\mathrm{V}_{\mathrm{E}}=0\, \mathrm{V}$
$\mathrm{v}_{\mathrm{B}}=-4 \,\mathrm{V}$
$\mathrm{V}_{\mathrm{A}}=5 \,\mathrm{V}$
So, potential difference between the points
$A$ and $D$
$V_{A}-V_{D}=5\, \mathrm{V}$
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(Take $1$ curie $= 3.7 × 10^{10}$ disintegration per second and ${e^{ - \lambda t}} = 0.7927;$ where $\lambda$= disintegration constant)
.......... $\mathrm{gm} / \mathrm{cm}^{3}$