MCQ
In the esterification reaction of alcohols
- ✓$O{H^ - }$ is replaced by $C{H_3}CO{O^-}$ group
- B$O{H^ - }$ is replaced by chlorine
- C${H^ - }$ is replaced by sodium metal
- D$O{H^ - }$is replaced by ${C_2}{H_5}OH$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${C_6}{H_5}N{H_2}\mathop {\xrightarrow{{NaN{O_2}/HCl}}}\limits_{0 - 5\,^o C} X\mathop {\xrightarrow{{HN{O_2}}}}\limits_{C{H_2}O} Y + {N_2} + HCl$
$X$ and $Y$ are respectively
$0.48 + \log \left\{ { - \frac{{d[A]}}{{dt}}} \right\} = \log \left\{ { + \frac{{d[B]}}{{dt}}} \right\} + 0.7$
Then, $x : y$ is
$x$ and $y$ mole consumed. Value of $x + y =$
